while执行两次的问题,已经解决
0赞//2013 5 11
//designer :pengxiaoen
// function change the number 'd' to 'b'
#include "stdio.h"
unsigned long int in_un_number;
char in_c_choice; int s[33];
int i;
void output_function ()
{
printf ("\nSUCCESS\n") ;
printf ("%d = (%d)",in_un_number,i);
for (i=i-1;i>=0;i--) printf ("%d",s[i]); printf ("\n\n\n");
}
void choice_function ()
{
printf ("please choice next operation:\n");
printf ("'c' for contiue\n");
}
void transform_function(unsigned long int temp)
{
i = 0;
temp = in_un_number;
while (temp != 0)
{
s[i] = temp % 2;
temp = temp /2;
i++;
}
}
int main ()
{
in_c_choice = 'c';
for (i=33;i>=0;i--) s[i] = 0;
printf ("The function is change 'd' to 'b'\n");
//-------------------------------------------------------------
while (in_c_choice == 'c')
{
printf ("Please enter your positive number : ");
scanf("%d",&in_un_number);
transform_function(in_un_number);
output_function();
choice_function();
scanf("%d",&in_c_choice);
}
system ("pause");
}
第一次键入值正确
可是当我再键入 c 的时候就出现了死循环
不知道为什么?????????????????????????????????????????????????????????
修改:
将scanf("%d",&in_c_choice);和choice_functon注释掉,正常
问题解决办法:
因为第二次执行scanf的时候,读取内存数据,由于上一次的残留,程序以外其中有数,输入完毕
解决办法 在scanf之前 清除缓存数据
fflush(stdin);